ICS Part 2 Physics Chapter 12 Short Questions Preparation


12th Class Physics
Short Questions Preparation

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Physics - ICS Part 2 Physics Chapter 12 Short Questions Preparation

Question # 1

Describe the force on positive charge when placed between parallel plates with opposite and equal charges.

  • Ans 1: When a positive point charge is placed between parallel plates with opposite but equal amount of charge ,then electric field intensity due to one plate is equal in magnitude but in same direction of the electric field intensity due to the other plate.So the value of resultant electric field intensity is non-zero.Hence the point charge will be accelerated towards negative plate.
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Prepare Complete Set Wise Questions For Chapter 1 "ICS Part 2 Physics Chapter 12 Short Questions Preparation "

ICS Part 2 Physics Chapter 12 Short Questions Preparation - Set 1

Question # 1

Describe the force on positive charge when placed between parallel plates with opposite and equal charges.

  • Ans 1: When a positive point charge is placed between parallel plates with opposite but equal amount of charge ,then electric field intensity due to one plate is equal in magnitude but in same direction of the electric field intensity due to the other plate.So the value of resultant electric field intensity is non-zero.Hence the point charge will be accelerated towards negative plate.
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ICS Part 2 Physics Chapter 12 Short Questions Preparation - Set 2

Question # 1

Electric lines of force never cross why?

  • Ans 1: Electric lines of force never cross each other,This is because that electric field line has only one direction at any given point.If the lines cross ,electric field lines could have more than one direction which is not possible.
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ICS Part 2 Physics Chapter 12 Short Questions Preparation - Set 3

Question # 1

Describe the force or forces on a positive point charge when placed between parallel plate,with similar and equal charges.

  • Ans 1: When a positive point charge is placed between parallel plates with similar and equal charges,then the electric field intensity due to one plate is equal in magnitude but opposite in direction of electric intensity due to other plate.So the value of resultant electric field intensity E is zero,Hence the net force on the positive charge is zero,Thus is will remain at rest.
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12th Chapter

ICS Part 2 Physics Chapter 12 Short Questions Preparation

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