ICS Part 2 Physics Chapter 13 Short Questions Preparation


12th Class Physics
Short Questions Preparation

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Physics - ICS Part 2 Physics Chapter 13 Short Questions Preparation

Question # 1

How a wheatstone bridge is used to determine an unknown resistance?

  • Ans 1: Wheatstone bridge is an especially designed electrically circuit used to calculate the accurate value of any unknown resistance.It consists of four resistance,a galvanometer, a battery and a switch connected.When the switch is closed current pas through the galvanometer and then the three known resistance R1,R2and R3are adjusted in such a way that galvanometer show no deflection,In this balanced condition the fourth unknown resistance R4can be calculated by using this relation.R1/R2=R3/R4.
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ICS Part 2 Physics Chapter 13 Short Questions Preparation - Set 1

Question # 1

How a wheatstone bridge is used to determine an unknown resistance?

  • Ans 1: Wheatstone bridge is an especially designed electrically circuit used to calculate the accurate value of any unknown resistance.It consists of four resistance,a galvanometer, a battery and a switch connected.When the switch is closed current pas through the galvanometer and then the three known resistance R1,R2and R3are adjusted in such a way that galvanometer show no deflection,In this balanced condition the fourth unknown resistance R4can be calculated by using this relation.R1/R2=R3/R4.
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ICS Part 2 Physics Chapter 13 Short Questions Preparation - Set 2

Question # 1

What does the equation H=I2Rt show?

  • Ans 1: This equation show the heating effect,During their motion free electrons collide frequently with the atom of metal.on each collision they transfer some of their kinetic energy to the atom with which they collide.And these collisions produce heating effect in the wire.
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ICS Part 2 Physics Chapter 13 Short Questions Preparation - Set 3

Question # 1

A voltmeter can not read the exact EMF of the cell.Why?

  • Ans 1: When a voltmeter is connected across a cell,it will draw some current from the cell and small potential drop takes place due current flowing through the internal resistance of the cell.As a result the actual emf of the cell decrease and the voltmeter cannot read exact value.
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13th Chapter

ICS Part 2 Physics Chapter 13 Short Questions Preparation

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