Matric Part 1/9th Class Physics Chapter 7 Long Question With Answer for Unit 7 Properties of Matter

Online Long Questions For Chapter 7 "9th Class Physics Chapter 7 Long Question Preparation "

Try The Long Questions For 9th Class Physics Chapter 7 Long Question Preparation

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Physics (New Book) - 9th Class Physics Chapter 7 Long Question Preparation

Question # 1

Q no: 7B) State Archimedes principle and prove it and derive equation of up thrust of liquid.

  • Ans 1: Archimedes Principle:
    When is totally or partially immersed in a liquid, an up thrust act on it equal to the weight of the liquid it displaces.
    Explanation:
    Consider a solid cylinder of cross-sectional area A and height h immersed in a liquid. Let h1 and h2 be the depth of the top and bottom surfaces of the liquid.
    Then
    h2-h1= h
    If P1 and p2 are the pressures at the depth h1 and h2 p is its density, then
    P1= pgh2
    P2= fgh2
    Let the force F1 is exerted the cylinder top by the liquid due to pressure P1 and the force F2 is exerted at the bottom of the cylinder due to P2
    So
    F1=pgh1A
    F2=pgh2A
    F1 and F2 are acting on the opposite faces of the cylinder. Therefore, the net force F will be F2- F1 in the direction of F2
    F2 - F1 = pgh2A -pgh1A
    =pgA(h2-h1)
    =pghA
    = pgV
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Prepare Complete Set Wise Questions For Chapter 7 "9th Class Physics Chapter 7 Long Question Preparation "

9th Class Physics Chapter 7 Long Question Preparation - Set 1

Question # 1

Q no: 7B) State Archimedes principle and prove it and derive equation of up thrust of liquid.

  • Ans 1: Archimedes Principle:
    When is totally or partially immersed in a liquid, an up thrust act on it equal to the weight of the liquid it displaces.
    Explanation:
    Consider a solid cylinder of cross-sectional area A and height h immersed in a liquid. Let h1 and h2 be the depth of the top and bottom surfaces of the liquid.
    Then
    h2-h1= h
    If P1 and p2 are the pressures at the depth h1 and h2 p is its density, then
    P1= pgh2
    P2= fgh2
    Let the force F1 is exerted the cylinder top by the liquid due to pressure P1 and the force F2 is exerted at the bottom of the cylinder due to P2
    So
    F1=pgh1A
    F2=pgh2A
    F1 and F2 are acting on the opposite faces of the cylinder. Therefore, the net force F will be F2- F1 in the direction of F2
    F2 - F1 = pgh2A -pgh1A
    =pgA(h2-h1)
    =pghA
    = pgV
Submit

9th Class Physics Chapter 7 Long Question Preparation - Set 2

Question # 1

State and explain Pascals law

  • Ans 1: Pascals law: pressure applied at any point of a liquid enclosed in a container, is transmitted without loss to all other parts of liquid

  • Ans 2: Explanation: consider a glass vessel. By pushing the piston exert force on water . this pressure is transmitted equally throughout the liquids in all directions water comes out of holes in vessel with some force.
  • Ans 3: Note: Pascals law hold good of fluid, liquid's and gases
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