ECAT Pre Computer Science MCQ Test For Computer Chapter 5 With Answer

MCQ's Test For ECAT Computer Science Chapter 5 Boolean Algebra

Try The MCQ's Test For ECAT Computer Science Chapter 5 Boolean Algebra

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ECAT Computer Science Chapter 5 Boolean Algebra

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Question # 1

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Question # 2

Boolean description for the exclusive OR gate for two inputs x and y can be written as.

Question # 3

The 'Boolean Algebra' is based on the premise that

Question # 4

Logical multiplication refers to operation of.

Question # 5

NAND gates are preferred over others because these.

Question # 6

In Boolean algebra A.0 is

Question # 7

The circuit that is used for parallel to serial conversion is

Question # 8

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Question # 9

Boolean expression for NOR gate with two inputs x and y can be written as.

Question # 10

The number of inputs to full adder are

Question # 11

The half adder circuit has

Question # 12

In a three input NAND gate, if all the inputs are 1, the output is.

Question # 13

If A and B are two 1-bit numbers, what logic gates will be required to test for A=B?

Question # 14

Which of the following gate is two level logic gate.

Question # 15

Which of the following operations are used by Boolean algebra.?

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ECAT Computer Sciences Chapter 5 Important MCQ's

Sr.# Question Answer
1 The 'Boolean Algebra' is based on the premise that
A. there are two states
B. differential equations can be solved by analog circuits.
C. either a statement is true or false
D. arithmetic operations can be carried out
2 If A and B are two 1-bit numbers, what logic gates will be required to test for A=B?
A. NOR gate
B. EXCLUSIVE OR gate
C. EXCLUSIVE NOT gate
D. OR gate
3 Boolean expression for NOR gate with two inputs x and y can be written as.
A. x + y__
B. x. y
C. x + y
4 Boolean algebra use which of the following to represent arithmetic quantities.
A. decimal digits
B. exponents
C. binary bits
D. fractions
5 According to Boolean algebra x + 1 = ______________
A. 0
B. 1
C. x
6 The commutative law in Boolean Algebra, where a, b and c are binary number is.
A. a+0=a
B. a+1=1
C. a+b=b+a
D. a. (b+c) = a.b +a.c.
7
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A. 0
B. 1
C. x
8
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A. A + B + C + D
C. A + B C + D
9 According to aborption law x+x.y=
A. x
B. y
C. 1 + x
D. 1 + y
10 According to absorption law x. (x+y) =
A. x
B. y
C. 1+x
D. 1+y

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