Past Paper 2025 12th Class Karachi Board Mathematics Objective (Science General Group)

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MATHEMATICS 2025

(Science General Group)

TIME: 3 Hours (100 Marks)

SECTION 'A' (Multiple Choice Questions)(20)

1. Choose the correct answer for each from the given options:

i) The “expand” compound in Maple software for (x + 1)(x + 2) is: *> expand((x + 1) * (x + 2)) ✓ *> expand((x + 1) + (x + 2)) *> expand(x2 + 3x + 2) *< exp((x + 1)(x + 2))

ii) To evaluate π to 6 digits, Maple command is: *> evalf(6Pi) ✓ *> evalf(Pi,6) *> evalf(6,Pi) *> evalf(6Pi)

iii) The interval [3,5] – (3,5) =: *∅ *(3,5) *[3,5] ✓ *[3,5]✓

iv) limx→0(1 + x)1/x =: *e *e2 *ex *ex

v) If y = tan−1√x then dy/dx =: *11+x2 *12√x(1+x) ✓ *1x+√x *11-x2

vi) The derivative of cot h−1(2x) is: *11-4x2 *11-4x2✓ *2x1-4x2 *21+4x2

vii) If f(x) = sin hx + cos hx, then f'(x) =: *0 *1 *f(x)✓ *-f(x)

viii) If S is the distance covered by a car, then d2S/dt2 will be its: *declaration *acceleration ✓ *Average velocity *Velocity

ix) Differentiation of a vector function f(k) = e2t + 1 î + sin(2t) ĵ + t2 k̂ with respect to 't' at t = 0 is: *2î + 2ĵ + 3k̂ *2ĵ + 3k̂ *2î + 3k̂ *2î + 2ĵ ✓

x) ∫−aa f(x) dx = where f(−x) = f(x) is: *0 *∫−aa f(x) dx *2a *2 ∫0a f(x) dx ✓

xi) ∫ tan 45° dx =: *sec 45° + c * ln sec 45° + c * cot 45° + c * x + c ✓

xii) The point where the medians of the triangle meet is called: *Centroid ✓ *Circumcentre *Incentre *Orthocentre

xiii) The equation of straight line which make intercepts 3 and 2 on the axes respectively is: *2x + 3y = 6 ✓ *3x + 2y = 0 *2x + 3y = 1 *3x + 2y = 3

xiv) In generally, the circle x2 + y2 + 2gx + 2fy + c = 0 is passing through the origin then: *c = 0 ✓ *g = 0 *f = 0 *g = f

xv) This radius of the circle x2 + y2 + 2gx + 2fy + c = 0: *√(g2 + f2 + c) *√(g2 − f2 + c) *√(−g2 + f2 + c) *√(g2 + f2 − c) ✓

xvi) The latus rectum of the parabola (y − 3)2 = −8(x + 4) is: *−2 *2 *8 ✓ *−8

xvii) The distance between the foci of an ellipse x2/a2 + y2/b2 = 1 is: *2a/e *2a *2ae ✓ *2b2/a

xviii) The general solution of the differential equation dy/dx = −y is:

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