PPSC Chemistry Part II Organic Chemistry Online Test With Answers

PPSC Chemistry Part II Organic Chemistry Online Test

Sr. # Questions Answers Choice
1 Alkaline hydrolysis of chloroform produces. HCCO HCOO - + CO H3COH CHCL2 OH
2 Which of the following alkyl halide undergoes nucleophilic substitution reaction via the formation of a carboncation. 1-chloro -2 methyl propane 2- chlro-2-methyl propane 2- chloro butane 1-Chloro, 3,3- dimethyl pentane
3 When alkyl iodidies are decomposed by light then the product obtained is. R - R R - H RCH2I RCHI2
4 Iodination of benzene takes place in the presence of iodine and HNO3 HIO3 HgO All of these
5 Chlorination of benzene with excess chlorine in the presence of FeCl3 as Lewis acid gives. Chlorobenzene as a major product o-dichlorobenzene as major product p-dichloro benzene as an only product A mixture of 0- and p- dichloro benzene
6 An optically active compound <sub>Must contain at least favour carbons</sub> When in solution rotate the plane of polarized light Most always contain an asymmetric carbon atom In solution always give negative reading in polarimetre
7 A molecule is said to be chiral If it contains plane of symmetry If it contains centre of symmetry If it can be superimposed on its mirror image None of the above
8 Plane polarized light is affected by Identical molecules All polymers Chiral molecules All biomolecules
9 It is possible to distinguish between optical isomers. Using chemical tests By mass spectrometry By IR spectroscopy By polarimetry
10 Enantiomers have which of the following characteristics. Rotate ordinary light Have the same melting point Are superimposable mirror images React with optically active molecule at the same rate
11 Which of the following statements is false about enantiomers. Rotate plane of polarized light Are superimposable mirror images Nbonsuperimposable mirror images All of the above
12 What is the possible number of optical isomers for a compound contained 2 dissimilar asymmetric carbon atoms. 2 4 6 8
13 Which of the following compound will be optically active. Suceinic acid Meso tartaric acid Acetic acid Lactic acid
14 2- Butanol is optically active because a contains An asymmetric carbon atom A plane of symmetry Centre of symmetry A hydroxyl group
15 Lactic acid is a molecule which shows Epimersim Tautomerism Opical isomerism Metamerism
16 Process of separating the racemic mixture into optically active isomers is known as. Resolution Racemisation Walden inversion Epimerization
17 How many stereoisomers are possible for CH3CH = CHCHCH(Br) CH3 2- geometrical isomers 2- optical isomers 2- geometricla nad 2- optical isomers 2- geometrical and 1 optical isomers
18 According to R, S system the correct order of priority of the following groups is . -CH2OH &gt; - CHO &gt; ----- COOH -COOH &gt; ------CHO &gt; ------CH2OH ---- CH2OH -----&gt; - COOH &gt; -------CHO --- COOH &gt; - CH2OH &gt;----- CHO
19 C is -2 butene on reaction with bromino give 2,3 -dibromobutane which is Recemic mixture Meso isomer Dextoroisomer Levoisomer
20 D(+) glyceraldebydes has the absolute configurtion. E- S- E- Z-
Download This Set

Is this page helpful?