MDCAT Physics Chapter 3 online mcq test with answers for chapter 3 (Rotational and Circular Motion)

Chapter 3 of Physics is an essential part of the MDCAT preparation. The students preparing for the exam must solve the MCQs available on this platform. For the convenience of the students, the answers are also uploaded here so the students can learn about their preparation level for the exam. The Chapter on Rotational and Circular Motion has various formulas that the students must memorize.

Besides cramming, the students should use logic to solve the questions of Physics. The candidates make sure to allocate the proper time to all the topics in this chapter. The practice helps the students to get good scores and strengthen their preparation before the commencement of the MDCAT exam. To get more information about the preparation of MDCAT, stay in touch with us and get a hand on the preparation material.

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MDCAT Physics Chapter 3 MCQ Test With Answer for ( Work ,Energy & Power)

MCQ's Test For MDCAT Physics Chapter 3 Work ,Energy & Power Online Test

MDCAT Physics Chapter 3 Work ,Energy & Power Online Test

In a gravitational field when work done by gravity is negative then

A body is dropped from a height of 20 m and rebounds to a height of 10 m. the loss of energy is:

Which of the following is a unit of energy?

A body of mass 3 Kg lies on the surface on the table 2m high. It is moved on the surface by 4m. The change of P.E will be:

If the stone is thrown up vertically and return to ground, its potential energy is maximum

Car X is traveling at half the speed of car Y. Car X has twice mass of car Y.Which statement is correct?

A ball is thrown vertically upwards. Neglecting air resistance, which statement is correct?

A person holds a bucket of weight 60N. He walks 7 m along the horizontal path and then climbs up a vertical distance of 5 m. The work done by the man is:

In an explosion a body breaks up into two pieces of unequal masses. In this:

3 joules of work is done in 3 seconds, then power is:

. A force "F1" acts on a body through distance "S1" in the direction of motion and does work "W1". Similarly another force "F2" act on same body through distance "S2" but in opposite to the direction of motion and does work "W2". Now if F1 = F2 and S1 = S2 then which statement is correct.

The time taken by an engine of power 10 kW to lift a mass of 200 kg to a heightof 40 m is (g + 10ms2)

When a person lifts a body from ground work done by lifting force is?

The momentum of a particle is numerically equal to its K.E. What is the velocity of a particle?

A person weighing 20 mg walks on a level platform with a speed of 2 ms-1 . The work by the person against the force of gravity is:

If the K.E. of a body is increased by 300%, its momentum will increase by:

The power needed to lift amass of 5000g to height of 1min 2 second is

A force 𝑭 = (𝟓𝒊̂+ 𝟑𝖩̂) newton is applied over a particle which displaces it from its origin to the point 𝒓 = (𝟐𝒊̂− 𝟏𝖩̂) meters. The work done on the particle is:

A 50 kg man with 20 kg load on his head climbs up 20 steps of 0.25 m height each. The work done in climbing is

An engine pumps up 100 kg of water through a height of 10m in 5s. Given that the efficiency of the engine is 60%, what is the power of the engine? (Take g = 10ms-2)

Prepare Complete Set Wise MDCAT Physics Chapter 3 Work ,Energy & Power Online Test MCQs Online With Answers

Set 1

Set 2

Set 3

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Test Questions

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Car X is traveling at half the speed of car Y. Car X has twice mass of car Y.
Which statement is correct?

An engine pumps up 100 kg of water through a height of 10m in 5s. Given that the efficiency of the engine is 60%, what is the power of the engine? (Take g = 10ms^-2)