Fsc physics part 2 test-Fsc Part 2 test for Physics chapter 12 electrostatics

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FSc Part II Physics Chapter 0 Important MCQ's

Sr.#	Question	Answer
1	One joule is equal to.	A. 1.6 x 10¹⁹ eV B. 1.6 x 10^-19 eV C. 6.25 x 10^-18 eV D. 6.25 x 10 ¹⁸ eV
2	Intensity of field inside a hollow charged sphere will be.	A. Negative B. Unaffected C. Zero D. Maximum
3	Presence of dielectric always.	A. Increase the electrostatic force B. Reduces the electrostatic force C. Do not effect electrostatic force D. Doubles the electrostatic force
4	For computation of electric flux, the surface area should be.	A. Parallel B. Flat C. Curved D. Spherical
5	A capacitor stores energy in the form of.	A. Magnetic field B. Heat energy C. Electrical energy D. Mechanical energy
6	Dielectric constant _εr for air is:	A. 1 B. 1.006 C. 1.0002 D. 1.0006
7	Electric potencial of earth is taken to be zero because the earth is good:	A. Semiconductor B. Conductor C. Insulator D. Dielectric
8	Due to polarization, electric field E.	A. Increase B. Decrease C. First increases then decreases D. Remain same
9	Net charge enclosed by Gaussian surface is:	A. zero B. maximum C. depend on intensity D. none of all
10	The electric intensity at infinite distance from the point charge is	A. Infinite B. Zero C. Positive D. Negative

Share your comments & questions here

Muhammad Rehman
10 Jul 2019

Nice way for preparation

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Kainat Ishfaq
09 May 2019

Today was my urdu board exam which mcqs r quite diffrent from online test prepration.Add more mcqs choice in test

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Hidayat ullah
30 Apr 2019

Physics mcqs

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Jamshaid
28 Apr 2019

Best question

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MEHTAB
12 Jan 2019

NICE PLACE TO STUDY

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Second Year Physics Chapter 12 Online MCQ Test for 2nd Year Physics "Electrostatics Preparation"

FSC Part 2 Physics Chapter 12 Test

FSC Part 2 Physics Chapter Wise Test (English Medium)

MCQ's Test For Chapter 0 "Physics FSC Part 2 Chapter 12 Online MCQ's Test"

Physics FSC Part 2 Chapter 12 Online MCQ's Test

Force per unit charge is called:

The electric flux through closed surface depends upon

The leV =

Which one is photo conductor.

The electric intensity due to two oppositely charged plates is

A force of 0.01 N is exerted on a charge 1.2 x 10-5 C at a certain point. The electric field at that point is

When some di electric is inserted between the plates of a capacitor, then capacitance.

For computation of electric flux, the surface area should be.

The electrostatic force between two charges is 42 N, If we place a dielectric of Ey=2.1 between the charges then the force become equal to.

Concept of electric field lines was given by:

A charge on 4 coulomb is in the field of intensity 4N/C the force on the charge is.

The electric intensity at infinite distance from the point charge is

Due to polarization, electric field E.

The toner of printer is given

The electric field in some region of of space is uniform in magnitude and direction. Which one of the following five statements best desccribes the volume charge density (ρ) , in this region of space?

Two oppositely charged balls A and B attract the third ball C, when placed near them turn by turn The third ball C must be.

The photo copying process is called

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FSC Part 2 Physics Chapter 12 Online Test MCQ's

Top Scorers Of Chapter 0 "Physics FSC Part 2 Chapter 12 Online MCQ's Test" MCQ`s Test

FSc Part II Physics Chapter 0 Important MCQ's

Test Questions

Share your comments & questions here

Muhammad Rehman

Kainat Ishfaq

Hidayat ullah

Jamshaid

MEHTAB

FSC Part 2 Physics
Chapter 12 Test

FSC Part 2 Physics Chapter Wise Test
(English Medium)

A force of 0.01 N is exerted on a charge 1.2 x 10^-5 C at a certain point. The electric field at that point is

The electrostatic force between two charges is 42 N, If we place a dielectric of E_y=2.1 between the charges then the force become equal to.