ECAT Pre General Science MCQ Test With Answer for Mathematics Chapter 16

• 
  A
• 
  B
• 
  C
• 
  D

If sin (πcosθ) = cos (πsinθ), then which of the following is correct?

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

If Sin A = sin B, cos A = cos B, then the value of A in terms of B is

• 
  A
• 
  B
• 
  C
• 
  D

• No solution A
• One real solution B
• More than one real solution C
• None of these D

• 
  A
• 
  B
• 
  C
• none of these D

The smallest positive root of the equation tan x - x = 0 lies on

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

• 30° A
• 45° B
• 60° C
• 75° D

The solution set of sin x + cos x = 0 is

• 
  A
• 
  B
• 
  C
• 
  D

If sin 6θ+ sin 4θ+ sin 2θ, thenθ=

• 
  A
• 
  B
• 
  C
• 
  D

• trigonometric equation A
• conditional equation B
• identity C
• None D

By expressing sin 125° in terms of trigonometrical ratios, answer will be

• sin 65° = 0.9128 A
• sin 55° = 0.8192 B
• sin 70° = 0.5384 C
• sin 72° = 0.1982 D

Sine rule for a triangle states that

• a/sin A = b/sin B = c/sin C A
• sin A/a = sin B/b = sin C/c B
• a/sin A + b/sin B + c/sin C C
• 2a/sin A = 2b/sin B = 2c/sin C D

The solution set of the equation 4 cos²x - 3 + 0 is

• 
  A
• 
  B
• 
  C
• none of these D

In a triangle ABC, if angle A = 72° , angle B = 48° and c = 9 cm then Ĉ is

• 69° A
• 66° B
• 60° C
• 63° D

• 
  A
• 
  B
• 
  C
• both a & c D

For Cosine Rule of any triangle ABC, b²is equal to

• a²- c²+ 2ab cos A A
• a³+ c³- 3ab cos A B
• a²+ c²- 2ac cos B C
• a²- c²4bc cos A D

In which quadrant is the solution of the equation sin x + 1 = 0

• I andII quadrants A
• II andIII quadrants B
• III andIVquadrants C
• none of these D

The number of values of x in the interval [0, 5π] satisfying the equation 3 sin²x - 7 sinx + 2 = 0 is

• 0 A
• 5 B
• 6 C
• 10 D

• A finite non-empty set A
• Null set B
• Both a and b C
• None of these D

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• none of these D

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• none of these D

cotθ= sin 2θifθ=

• 
  A
• 
  B
• 
  C
• 
  D

General solution of tan 5θ= cot 2θis

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• all D

• I andII quadrants
  A
• II andIII quadrants B
• II andIVquadrants C
• none of these D