ECAT Pre Engineering Mathematic MCQ Test With Answer for Chapter 16 (Solution of Trigonometric Equation)

By expressing cos 113° in terms of trigonometrical ratios, answer will be

• − cos 76° = -0.7093 A
• − cos 65° = -0.4258 B
• − cos 67° = -0.3907 C
• − cos 62° = -0.8520 D

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

• A finite non-empty set A
• Null set B
• Both a and b C
• None of these D

The general value ofθsatisfying the equation 2 sin²θ- 3 sinθ-2 = 0 is

• 
  A
• 
  B
• 
  C
• 
  D

Considering Cosine Rule of any triangle ABC, possible measures of angle A includes

• Angle A is obtuse A
• Angle A is acute B
• Angle A is right-angle C
• All of above D

If sin 6θ+ sin 4θ+ sin 2θ, thenθ=

• 
  A
• 
  B
• 
  C
• 
  D

The number of points of intersection of two curves y = 2 sin x and y = 5x²+ 2x + 3 is

• 0 A
• 1 B
• 2 C
• None of these D

• 
  A
• 
  B
• 
  C
• none of these D

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

If sin (πcosθ) = cos (πsinθ), then which of the following is correct?

• 
  A
• 
  B
• 
  C
• 
  D

By expressing sin 125° in terms of trigonometrical ratios, answer will be

• sin 65° = 0.9128 A
• sin 55° = 0.8192 B
• sin 70° = 0.5384 C
• sin 72° = 0.1982 D

The solution set of trigonometric equation contains

• one element A
• two elements B
• three elements C
• Infinite elements D

• trigonometric equation A
• conditional equation B
• identity C
• None D

• 
  A
• 
  B
• 
  C
• 
  D

In which quadrant is the solution of the equation sin x + 1 = 0

• I andII quadrants A
• II andIII quadrants B
• III andIVquadrants C
• none of these D

Sine rule for a triangle states that

• a/sin A = b/sin B = c/sin C A
• sin A/a = sin B/b = sin C/c B
• a/sin A + b/sin B + c/sin C C
• 2a/sin A = 2b/sin B = 2c/sin C D

• 
  A
• 
  B
• 
  C
• all D

The solution set of sin x + cos x = 0 is

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• none of these D

If Sin A = sin B, cos A = cos B, then the value of A in terms of B is

• 
  A
• 
  B
• 
  C
• 
  D

• 
  A
• 
  B
• 
  C
• 
  D

• 30° A
• 45° B
• 60° C
• 75° D

In a triangle ABC, if angle A = 72° , angle B = 48° and c = 9 cm then Ĉ is

• 69° A
• 66° B
• 60° C
• 63° D

• 
  A
• 
  B
• 
  C
• 
  D

cotθ= sin 2θifθ=

• 
  A
• 
  B
• 
  C
• 
  D

The general solution of tan 3x = 1 is

• 
  A
• 
  B
• 
  C
• 
  D

cotθ= sin 2θifθ=

• 
  A
• 
  B
• 
  C
• 
  D