More Classes
5th Class
6th Class
7th Class
8th Class
9th Class
10th Class
11th Class
12th Class
NAT I
NAT II
CSS
IQ
General Knowledge
MDCAT
ECAT
GAT General
GAT Subject
Other Links
Go to Home
Online Tests
MTH-101 Final Term Exams Preparation Virtual University MCQs With Answers
Question # 1
If a function g is differentiable at a point x and function f is differentiable at a point g(x),then the __ is differentiable a point x.
Choose an answer
Composition (fog)
Quotient f/g
product f.g
Sum (f+g)
Previous
Skip
Next
Question # 2
Which operation could not be applied on the function?
Choose an answer
Cross Product
Sum
Division
Previous
Skip
Next
Question # 3
Sigma notation is represent by
Choose an answer
M
N
Σ
Previous
Skip
Next
Question # 4
Which operation can not be applied on the function?
Choose an answer
Subtraction
Cross Product
Addition
Composition
Previous
Skip
Next
Question # 5
a function f is ___ on a closed interval [a,b] ,then f has both a maximum and minimum value on [a,b]
Choose an answer
Continuous
Discontinuous
None of these
Previous
Skip
Next
Question # 6
if xy=4 then dy/dx =?
Choose an answer
0
-1/x
2
-4/x
2
Previous
Skip
Next
Question # 7
The PYTHAGORAS theorem describe the relationship between the sides of
Choose an answer
Right angle triangle
Isoceleous Triangle
Equilateral traingle
Previous
Skip
Next
Question # 8
Suppose f and g are differentiable function of x then d/dx[f/g]
Choose an answer
[g][f'] - [f][g']/g
2
[g'][f] - [f'][g]/g
2
[g'][f] - [f'][g]/f
2
Previous
Skip
Next
Question # 9
For a graph to be symmetric about y axis mean ,for each point (x,y) on the graph the point ____ is also on the graph
Choose an answer
(x,-y)
(-x,y)
(-x,-y)
Previous
Skip
Next
Question # 10
Consider two function f(x)=x
3
and g(x)=(x+9) then fog(x)=
Choose an answer
(x+9)3
x+3
x+9
Previous
Skip
Next
Question # 11
The mean value of theorem states that " Let function f can be differentiable on (a,b) and continuous on [a,b] then there is no exist at least one point c in (a,b) where ______
Choose an answer
f'(c)=f(b)-f(a)/b-a
f(c)=f(b)-f(a)/b-a
f(c)=f(a)-f(b)/b-a
Previous
Skip
Next
Back