Question # 1

Total flux through a closed surface depends on.

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Shape of surface

Medium only

Charge enclosed only

Charge and Medium

The negative of the potential gradient is

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Electrostatic force

Electromotive force

Potential difference

Electric field intensity

Electro encephalon graph is the diagnostic test for the working of.

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Eye

Heart

Brain

Lungs

Which one of the following is correct

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All of above

The amount of energy equal to 1.6 x 10^-18 J is called.

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One volt

One milli volt

One electron volt

One mega electron volt

One joule is equal to.

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1.6 x 10¹⁹ eV

1.6 x 10^-19 eV

6.25 x 10^-18 eV

6.25 x 10 ¹⁸ eV

The toner of printer is given

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Positive charge

Negative charge

Neutral

First positive then negative

The electric potential at a mid point in an electric dipole is.

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0 V

0.5 V

1 V

1.5 V

The process of copying is:

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Axillugraphy

Chromatography

Xerography

Spectrography

The force of Neutron due to field of 10² N/C is.

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1.6 x 10^-17N

1.6 x 10^-19N

Zero

1.6 x 10^-21N

If a charged body is moved against the electric field it will gain.

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P.E.

K.E.

Mechanical energy

Electrical potential energy

The number of lines per unit area passing perpendicular through an area is called

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Flux

Electric intensity

Both (a) , (b)

None of these

Capacitance of a capacitor does not depend upon.

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Distance between plates

Area of plates

Electric field between plates

Medium between plates

Which material should be inserted between the plates of a capacitor in order to increase its capacitance.

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Copper

Mica

Iron

Tin

The electric field created by positive charge is

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Radially inward

Zero

Circular

Radially outward

The middle region of electric field is:

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Maximum field spot

Zero field spot

Perpendicular field spot

All of above

In photocopier, then drum is coated with layer of.

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Aluminium

Copper

Selenium

silver

The product of resistance and capacitanc eis.

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Velocity

Force

Acceleration

Time

Identify the practical application of electrostatic force.

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Inkjet printer

x rays

Laser

A.C. Generator

The electric flux through closed surface depends upon

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Charge

Medium

Geometry

Charge and Medium

Coulomb /volt is called.

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Farad

Ampere

Joule

Henry

Electric potential at a distance ''r'' from ''q'' is:

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V_r = 1/54πε_∘q/r₂

Vr=1/4πε_∘²q/r

V_r=1/4πε_∘2q/r

V_r=1/4πε_∘q²/r

The electrical intensity is equal to:

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-Δr/Δv

Δv/Δr

Δv/Δv

-Δv/Δr

Concept of electric field lines was given by:

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Michelson

Henry

Michael faraday

Oersted

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