Question # 1

Identify the practical application of electrostatic force.

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Inkjet printer

x rays

Laser

A.C. Generator

If a charged body is moved against the electric field it will gain.

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P.E.

K.E.

Mechanical energy

Electrical potential energy

Which material should be inserted between the plates of a capacitor in order to increase its capacitance.

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Copper

Mica

Iron

Tin

The electric field created by positive charge is

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Radially inward

Zero

Circular

Radially outward

Electric potential at a distance ''r'' from ''q'' is:

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V_r = 1/54πε_∘q/r₂

Vr=1/4πε_∘²q/r

V_r=1/4πε_∘2q/r

V_r=1/4πε_∘q²/r

Capacitance of a capacitor does not depend upon.

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Distance between plates

Area of plates

Electric field between plates

Medium between plates

Electric potencial of earth is taken to be zero because the earth is good:

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Semiconductor

Conductor

Insulator

Dielectric

The net charge on a capacitor magnitude of charge of charge

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Infinity

2 q

Q/2

Zero

Which one of the following is correct

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All of above

The "toner" of photocopier is given:

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Positive charge

Negative charge

Remains neutral

All of above

Electric flux is a:

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Scalar quantity

Vector quantity

Variable quantity

None of these

Metals are good conductors of electricity because they have

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Large number of bounded electrons

Small number of electrons

Large number of free electrons

Small number of free electrons

Total flux through a closed surface depends on.

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Shape of surface

Medium only

Charge enclosed only

Charge and Medium

If the medium between the charges is not free space then electrostatic force will.be

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Increase

Decrease

Remain same

None of these

The fact that electric field exist in space around an electrical charge is

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Electrical property

Gravitational property

Intrinsic property of nature

Extrinsic property of nature

The work done is bringing a unit positive charge from infinity to that point in an electric field is called.

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Potential

Potential difference

Absolute potential

All of these

Selenium is a

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Insulator

Photoconductor

Conductor

First insulator then conductor

One joule is equal to.

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1.6 x 10¹⁹ eV

1.6 x 10^-19 eV

6.25 x 10^-18 eV

6.25 x 10 ¹⁸ eV

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