Question # 1

An electron of charge e coulomb passes through a potential difference of V volts its energy in joules will be

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V/e

eV

e/V

V

The energy stored in a charge capacitor

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1/2CV²

1/2C²V

1/2C/V²

None of these

The SI unit of current is

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watt

coulomb

volt

ampere

The electric lines of force are

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Imaginary

Physically existing everywhere

Physically existing near the charge

All of the above

If the distance of separation between two chares is increased, the electrical potential energy of the system will

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Increase

Decrease

May increase or decrease

Remain the same

At any point on the right bisector of the line joining two equal and opposite charges

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At electric field is zero

The electric potential is zero

The electric potential decreases with increasing distance from the centre

The electric field is perpendicular to the line joining the charges

A current of 1.6 A is passed through a solution of CuSO_{4. How many Cu}²⁺ions are liberated in one minute?

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3 x 10²⁰

3 x 10¹⁰

6 x 10²⁰

6 x 10¹⁰

The concept of field theory was put forward by

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Franklin

Kepler

Oersted

Michael Faraday

The unit of intensity of electric field is

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newton/coluomb

jule/coluomb

volt x metre

newton/metre

The current through a metallic conductor is due to the motion of

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protons

neutrons

electrons

free electrons

A medium of dielectric constant 'K' is introduced between the plates of parallel plate condenser. As a result its capcitance

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Increase k time

Decreases k times

Decreases 1/K times

Remains unchanged

The potential difference across each resistance in series combination is

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same

different

zero

none of these

One moving a charge of 20 coulombs by 2 cm, 2 J of work is done, then the potential difference between the points is

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0.1 V

8 V

2 V

0.5 V

One coulomb of charge is created by

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10 electrons

1.6 x 10^-19electrons

6.25 x 10¹⁸electrons

6.25 x 10²¹electrons

If one volt is needed to cause a current of one ampere to flow in a conductor, its resistance is

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one ohm

one joule

one volt

one ampere

A heater coil rated at (1000 W - 200 V) is connected to 110 volt line. What will be the power consumed?

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200 W

302.5

250 W

350 W

A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

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Increases

Decreases

Remain unchanged

Becomes infinite

A conducting wire is drawn to double its length. Final resistivity of the material will be

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Double of the original one

Half of the original one

One fourth of the original one

Same as original one

In bringing an electron towards another electron, electrostatic potential energy of system

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Decreases

Increases

Remains uncharged

Becomes zero

The charge carriers in electrolyte are positive and negative

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protons

electrons

ions

none of these

A wire is bent into a ring of radius R is given a charge q. The magnitude of the electrical field at the centre of the ring is

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Two

1/2

Zero

3/2

The powers of tow electric bulbs are 100 W and 200 W. Both of them are joined with 220 V mains. The ratio of resistances of their filaments will be

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1 : 2

2 : 1

1 : 4

4 : 1

For two resistance wires joined in parallel, the resultant resistance is 6/5 ohm. When one of the resistance wire breaks, the effective resistance becomes 2 ohm. The resistance of the broken wire is

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3/5 ohm

2 ohm

6/5 ohm

3 ohm

The unit of resistance is

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volt

ampere

ohm

coat

The electric field intensity at a point due to a point charge

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Falls off inversely as the distance

Falls off inversely as the square of distance

Remains unchanged with distance

Increase directly as square of distance

Three resistance 500,500 and 50 ohms are connected in series across 555 volts mains. The current flowing through them will be

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0.52 A

1 mA

0.7 mA

1.4 A

The SI unit of electric flux is

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Weber

Nm²C^-1

NmC^-1

Nm^-2C

If electric and gravitational force on an electron in a uniform electric field will be

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E=mg/q

E=q/mg

E=,g/q

E=qg/m

A uniform resistance wire of Length L and diameter d has a resistance R. Another wire of same material has length, 4L and diameter 2d, the resistance will be

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2 R

R

R/2

R/4

A piece of fuse wire melts when a current of 15 ampere flows through it. With this current. If it dissipates 22.5 W, the resistance of fuse wire will be

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Zero

10Ω

1Ω

0.10Ω

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