Question # 1

The in-centre of triangle whose vertices are (0,0), (5,12) and (16,12) is:

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(9,7)

(2,7)

(9,2)

(7,9)

The distance between two parallel lines 2x - 5y + 13 = 0 and -2x +5y -6 = 0 is:

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√29

8/√29

7 /√29

29√7

Shifting origin to (-3,2), the new coordinate of (-2,6) are:

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(1,4)

(2,4)

(-1,3)

(-1,4)

The slope of the line from B (2,-3) through A (0,3) is:

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-3

1/3

0

undefined

The equation of the line through (-8, 5) having slope undefined is:

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y + 8 = 0

y = 8

y = x + 8

x + 8 = 0

If the points (a,b), (x,y) and (a-x, b-y) are collinear, then ay =

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bx

b-y

a-x

x

The cartesian system of coordinates was introduced by:

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Eulaer

Euclid

Descrates

Maclream

If a point (p,q) is equidistant from the points (5,3) and (-2,-4), then p+ q =

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-1

1

3

-3

The quadrilateral with the vertices (-3,-2), (2,-1), (3,4) and (-2,3) is a:

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Square

Rectangle

rhombus

parallelogram

x-axis divides the line segment joining points (2,-3) and (5,6) in the ratio:

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2 : 1

-2 : 1

1 : 2

-1 : 2

Shifting origin to (1,-2), the new coordinates of (4,5) are:

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(3,7)

(5,3)

(-3,7)

(3,-7)

The distance between the parallel lines 3x - 4y + 3 =0 and 3x -4y + 7 = 0 is:

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2/3

9/13

4/5

7/12

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ECAT Pre General Science Mathematics Chapter 20 Analytic Geometry Online Test MCQs With Answers

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