Question # 1

(11)₂ x (11)₂ =

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(1001)₂

(10101)₂

(1100)₂

(1111)₂

If the right angled triangle the lengths of bas and perpendicular are 4 cm and 5 cm, then the length of hypotenuse will be

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√(31 cm)

√(41 cm)

8 cm

6 cm

Number of vertices of a hexagon is:

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3

4

5

6

Factorization of x² -25 is:

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(x-5)(x+5)

(x+5)(x+5)

(x-5)(x-5)

(5-x)(5+x)

(2.1)² - (0.2)²

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4.37

1.27

3.27

1.08

(x-y)²- 25 =

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(x-y-5)(x-y-5)

(x+y+5)(x+y+5)

(x-y-5)(x-y+5)

(x+y-5)(x+y+5)

(564)₈ + (431)₈

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(1215)₈

(1251)₈

(12115)₈

(2511)₈

x²+8x+16 =

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(x-16)²

(x+16)²

(x+4)²

(x-4)²

∛64 =

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2

4

8

10

(24)₈ x (42)₈

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(1010)₈

(1030)₈

(1250)₈

(1230)₈

4y²-12y+9 =

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(4y-9)²

(4y+9)²

(2y-3)²

(2y+3)²

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Mathematics 8th Class Urdu Medium Chapter 4 Online Test MCQs With Answers

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