Question # 1

A line perpendicular to a radial chord of a circle at the end-point (which lies on the circle) is a:

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Secant

Diameter

Chord

Tangent

The conic is a parabola, if:

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e = 1

e > 1

0 < e < 1

e = 0

The vertex of the parabola y² = 4ax is:

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(-a, 0)

(a, 0)

(0, -a)

(0, 0)

The point where the axis meets the parabola is called ________ of the parabola:

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Directrix

Vertex

Focus

Eccentricity

Perpendicular dropped from the center of a circle on a chord _______ the chord:

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Normal

Bisects

Equal to

None of these

The center of circle (x+3)² + (y-2)² = 16 equals:

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(-3, 2)

(3, -2)

(3, 2)

(-3, -2)

The focus of the parabola x² = 4ay:

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(0, a)

(-a , 0)

(0, -a)

(a, 0)

In equation of circle, coefficient of each of x² and y² are:

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Not equal

Opposite in signs

Equal

None of these

Two circles of radius 3 cm and 4 cm touch each other externally. The distance between their centers is:

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1 cm

7cm

4cm

5cm

The fixed point of the conic is called:

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Directrix

Vertex

Focus

None of these

The graph of the parabola x² = -4ay lies in quadrants:

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I and II

III and IV

II and III

I and III

The graph of the parabola y² = -4ax is symmetric about:

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x-axis

major axis

y-axis

minor axis

One of the angles of a triangle inscribed in a circle is of 40°. If one of its' the diameter, the other angles have the measures:

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30°, 110°

40°, 100°

50°, 90°

20°, 120°

If the equation of the parabola is y² = - 4ax, then opening of the parabola is to the ______ of the y-axis:

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Left

Upward

Right

Downward

The vertex of the parabola x² = 4ay is:

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(-a, 0)

(0, a)

(0, -a)

(0, 0)

The opening of the parabola y² = 4ax is to the ________ of the:

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Left

Upward

Right

Downward

The focus of the parabola y²=-4ax is:

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(-a , 0)

(0, a)

(0, -a)

(a, 0)

The focus of the parabola x2=-4ay is:

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(-a , 0)

(0, a)

(0, -a)

(a, 0)

A line segment joining two distinct points on a parabola is called a ___________ of the parabola:

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Chord

Vertex

Focus

Directrix

The opening of the parabola y² = -4ax is to the left of the:

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x-axis

x = 1

y-axis

x = 0

If the equation of the parabola is y2 = 4ax, then opening of the parabola is to the right of the:

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x-axis

y = x

y-axis

x + y =0

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