Question # 1

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range of f

domain of f

both (a) and (b)

none of these

Domain of cosh x is

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R

R -{0}

[1,∞)

[0,∞)

A function in which the variable appears as exponent is called:

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An identity function

A logarithmic function

an exponential function

A rational function

A function of the form p(x)/Q(x) is called:

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Rational function

Logarithmic function

Exponential function

Hyperbolic function

A function from X to X is denoted as

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f : X to Y

f : Y to Y

The domain of f(x) = log x is

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[0,∞]

(0,∞)

[0,∞[

[∞,∞]

The domain the function : f(x) = x² is given by

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R

Set of all non-negative Real numbers

R^-1

None of these

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1/8

1/2

1/4

1/6

Every relation, which can be represented by a linear equation in two variables, represents a

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Relation

Cartesian product

Function

Graph

The range of function f(x)=-x2+2x-1 is

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R

(-∞,0]

(-∞,1]

[0,∞)

If the domain of the function f: x⟶ 2x³+ 1 is {-1,2,3}, the range of the function is

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{3,2,5}

{1,3,9}

{-1,-2,-3}

{3,9,19}

In natural logarithm the base is

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1

0

10

e

If x is an image of y under the function f. This can be written as

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y = f(x)

f(x) = 0

x = f(y)

f(y) =0

If f(x) = x³- 2x²+ 4x -1 then f(2) is

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7

-16

16

-9

f(x) = x is

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trigonometric function

exponential function

quadratic function

identify function

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sin h x

cos h x

tan h x

cot h x

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Sin h^-1x = _________

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In the function f: A⟶B, the elements of a are called

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Images

Pre-images

ranges

Parameters

The range of inequality x + 2 > 4 is

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(-1, 2)

(-2, 2)

(1,∞)

None

f(x) = ax + b will be an identity function if

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a = 1 , b = 1

a = 1 , b = 0

If f (x) is defined and continuous then f (x) is always

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Rational function

Trigonometric function

Logarithmic function

All are correct

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f(x) = x3-x/x2+1 is :

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an even function

an odd function

an even and implicit function

neither even nor a odd

Domain of y = scs x is

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All real numbers except π/2 + n*π

R

All negative integers

None of these

If f(x) = -x³then f(-2) is

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-2

-4

-8

8

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3/4

r

v

None of these

A function from A to B is denoted by

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f: A→ B

f: B → A

f: → A :B

f → A→ B

Composition of functions is

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Non-commutative (fg ≠ gf)

non-associative [8(fh) ≠(8f)h]

Commutative (fg = gf)

f of-1≠ 1

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2

-1

8

not defined

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